The volume of irregular object computations.
Trapezoidal rule
A = L/2[01, + ON+ 2(02 + O3 + O4 +……+ ON-1)]…………………….. (i)
Problem 2
The following, offsets 8m apart, were measured at right angles from a
traverse line to an irregular Boundary. 0 m, 2.3 m, 5.5 m, 7.9 m, 8.6 m,
6.9 m, 7.3 m, 6.2 m, 3.1 m, and O m.
Calculate the area between the traverse line and the irregular boundary.
Solution:
From the general trapezoidal rule, area is given by.
A = L/2[01 + O10+ 2(02 + O3 + O4 +05 +06 +07 +08+ O9)]
In this case L = 8m.
Thus: A = 8/2[0 + 0 + 2(2.3 + 5.5 + 7.9 + 8.6 + 6.9 + 7.3+ 6.2 + 3.1)]
= 4[2(47.8)] = 382.4m2
