Problem 05 solved, Computation of area volumes.
Computation of area volumes. Problem 05 (A) The Following Offsets Were Taken from A Chain Line to An Irregular Boundary Line at an Interval Of 10 M.: 3.10, 4.20, 5.35, 6.45, 7.15, 8.25, 7.95, and
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Category: Engineering Survey
Problem 04 solved, Volume of area computations.
Volume of area computations. Problem 4. A, B, C, and D are the four clockwise considered boundary points of a plot. Sides AB and BC are straight, while sides CD and DA are irregular, with
Problem 03 Solved, Volume of irregular object computations.
The volume of irregular object computations. Simpson’s rule A = L/3[O1 + ON+ 4∑even offsets + 2∑remaining odd offsets] Problem 3. Consider the offsets measured from line AB to the irregular boundary as given in the
Problem 02 Solved, Volume of irregular object computations.
The volume of irregular object computations. Trapezoidal rule A = L/2[01, + ON+ 2(02 + O3 + O4 +……+ ON-1)]…………………….. (i) Problem 2 The following, offsets 8m apart, were measured at right angles from a
Problem solved; A theodolite whose constants are K= 100 and C=0
A theodolite Stations M, N, and P are for a right-angled triangle at station M as shown below. A theodolite whose constants are K= 100 and C=0 was used to determine the following chemometric data.
Problem 2.18 Reciprocal leveling involving a single. solved
2.18 Reciprocal leveling involving.. single level was used to transfer height. across a river between two points R1 and R2 70 m apart. Using the following readings, calculate the height change from R1 to R2